Optimal. Leaf size=274 \[ \frac {7 e (b d-a e) (4 b B d+5 A b e-9 a B e) \sqrt {d+e x}}{4 b^5}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{3/2}}{12 b^4}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}-\frac {7 e (b d-a e)^{3/2} (4 b B d+5 A b e-9 a B e) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 b^{11/2}} \]
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Rubi [A]
time = 0.16, antiderivative size = 274, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {79, 43, 52, 65,
214} \begin {gather*} -\frac {7 e (b d-a e)^{3/2} (-9 a B e+5 A b e+4 b B d) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 b^{11/2}}+\frac {7 e \sqrt {d+e x} (b d-a e) (-9 a B e+5 A b e+4 b B d)}{4 b^5}+\frac {7 e (d+e x)^{3/2} (-9 a B e+5 A b e+4 b B d)}{12 b^4}+\frac {7 e (d+e x)^{5/2} (-9 a B e+5 A b e+4 b B d)}{20 b^3 (b d-a e)}-\frac {(d+e x)^{7/2} (-9 a B e+5 A b e+4 b B d)}{4 b^2 (a+b x) (b d-a e)}-\frac {(d+e x)^{9/2} (A b-a B)}{2 b (a+b x)^2 (b d-a e)} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 52
Rule 65
Rule 79
Rule 214
Rubi steps
\begin {align*} \int \frac {(A+B x) (d+e x)^{7/2}}{(a+b x)^3} \, dx &=-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {(4 b B d+5 A b e-9 a B e) \int \frac {(d+e x)^{7/2}}{(a+b x)^2} \, dx}{4 b (b d-a e)}\\ &=-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {(7 e (4 b B d+5 A b e-9 a B e)) \int \frac {(d+e x)^{5/2}}{a+b x} \, dx}{8 b^2 (b d-a e)}\\ &=\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {(7 e (4 b B d+5 A b e-9 a B e)) \int \frac {(d+e x)^{3/2}}{a+b x} \, dx}{8 b^3}\\ &=\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{3/2}}{12 b^4}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {(7 e (b d-a e) (4 b B d+5 A b e-9 a B e)) \int \frac {\sqrt {d+e x}}{a+b x} \, dx}{8 b^4}\\ &=\frac {7 e (b d-a e) (4 b B d+5 A b e-9 a B e) \sqrt {d+e x}}{4 b^5}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{3/2}}{12 b^4}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {\left (7 e (b d-a e)^2 (4 b B d+5 A b e-9 a B e)\right ) \int \frac {1}{(a+b x) \sqrt {d+e x}} \, dx}{8 b^5}\\ &=\frac {7 e (b d-a e) (4 b B d+5 A b e-9 a B e) \sqrt {d+e x}}{4 b^5}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{3/2}}{12 b^4}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}+\frac {\left (7 (b d-a e)^2 (4 b B d+5 A b e-9 a B e)\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b d}{e}+\frac {b x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{4 b^5}\\ &=\frac {7 e (b d-a e) (4 b B d+5 A b e-9 a B e) \sqrt {d+e x}}{4 b^5}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{3/2}}{12 b^4}+\frac {7 e (4 b B d+5 A b e-9 a B e) (d+e x)^{5/2}}{20 b^3 (b d-a e)}-\frac {(4 b B d+5 A b e-9 a B e) (d+e x)^{7/2}}{4 b^2 (b d-a e) (a+b x)}-\frac {(A b-a B) (d+e x)^{9/2}}{2 b (b d-a e) (a+b x)^2}-\frac {7 e (b d-a e)^{3/2} (4 b B d+5 A b e-9 a B e) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 b^{11/2}}\\ \end {align*}
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Mathematica [A]
time = 0.97, size = 309, normalized size = 1.13 \begin {gather*} \frac {\sqrt {d+e x} \left (-5 A b \left (105 a^3 e^3+35 a^2 b e^2 (-4 d+5 e x)+7 a b^2 e \left (3 d^2-34 d e x+8 e^2 x^2\right )+b^3 \left (6 d^3+39 d^2 e x-80 d e^2 x^2-8 e^3 x^3\right )\right )+B \left (945 a^4 e^3+105 a^3 b e^2 (-16 d+15 e x)+7 a^2 b^2 e \left (107 d^2-406 d e x+72 e^2 x^2\right )+4 b^4 x \left (-15 d^3+116 d^2 e x+32 d e^2 x^2+6 e^3 x^3\right )-a b^3 \left (30 d^3-1303 d^2 e x+944 d e^2 x^2+72 e^3 x^3\right )\right )\right )}{60 b^5 (a+b x)^2}+\frac {7 e (-b d+a e)^{3/2} (4 b B d+5 A b e-9 a B e) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{4 b^{11/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.14, size = 467, normalized size = 1.70 Too large to display
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.18, size = 1020, normalized size = 3.72 \begin {gather*} \left [\frac {105 \, {\left ({\left (9 \, B a^{4} - 5 \, A a^{3} b + {\left (9 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} x^{2} + 2 \, {\left (9 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} x\right )} e^{3} - {\left ({\left (13 \, B a b^{3} - 5 \, A b^{4}\right )} d x^{2} + 2 \, {\left (13 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} d x + {\left (13 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} d\right )} e^{2} + 4 \, {\left (B b^{4} d^{2} x^{2} + 2 \, B a b^{3} d^{2} x + B a^{2} b^{2} d^{2}\right )} e\right )} \sqrt {\frac {b d - a e}{b}} \log \left (\frac {2 \, b d - 2 \, \sqrt {x e + d} b \sqrt {\frac {b d - a e}{b}} + {\left (b x - a\right )} e}{b x + a}\right ) - 2 \, {\left (60 \, B b^{4} d^{3} x + 30 \, {\left (B a b^{3} + A b^{4}\right )} d^{3} - {\left (24 \, B b^{4} x^{4} + 945 \, B a^{4} - 525 \, A a^{3} b - 8 \, {\left (9 \, B a b^{3} - 5 \, A b^{4}\right )} x^{3} + 56 \, {\left (9 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} x^{2} + 175 \, {\left (9 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} x\right )} e^{3} - 2 \, {\left (64 \, B b^{4} d x^{3} - 8 \, {\left (59 \, B a b^{3} - 25 \, A b^{4}\right )} d x^{2} - 7 \, {\left (203 \, B a^{2} b^{2} - 85 \, A a b^{3}\right )} d x - 70 \, {\left (12 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} d\right )} e^{2} - {\left (464 \, B b^{4} d^{2} x^{2} + {\left (1303 \, B a b^{3} - 195 \, A b^{4}\right )} d^{2} x + 7 \, {\left (107 \, B a^{2} b^{2} - 15 \, A a b^{3}\right )} d^{2}\right )} e\right )} \sqrt {x e + d}}{120 \, {\left (b^{7} x^{2} + 2 \, a b^{6} x + a^{2} b^{5}\right )}}, -\frac {105 \, {\left ({\left (9 \, B a^{4} - 5 \, A a^{3} b + {\left (9 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} x^{2} + 2 \, {\left (9 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} x\right )} e^{3} - {\left ({\left (13 \, B a b^{3} - 5 \, A b^{4}\right )} d x^{2} + 2 \, {\left (13 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} d x + {\left (13 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} d\right )} e^{2} + 4 \, {\left (B b^{4} d^{2} x^{2} + 2 \, B a b^{3} d^{2} x + B a^{2} b^{2} d^{2}\right )} e\right )} \sqrt {-\frac {b d - a e}{b}} \arctan \left (-\frac {\sqrt {x e + d} b \sqrt {-\frac {b d - a e}{b}}}{b d - a e}\right ) + {\left (60 \, B b^{4} d^{3} x + 30 \, {\left (B a b^{3} + A b^{4}\right )} d^{3} - {\left (24 \, B b^{4} x^{4} + 945 \, B a^{4} - 525 \, A a^{3} b - 8 \, {\left (9 \, B a b^{3} - 5 \, A b^{4}\right )} x^{3} + 56 \, {\left (9 \, B a^{2} b^{2} - 5 \, A a b^{3}\right )} x^{2} + 175 \, {\left (9 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} x\right )} e^{3} - 2 \, {\left (64 \, B b^{4} d x^{3} - 8 \, {\left (59 \, B a b^{3} - 25 \, A b^{4}\right )} d x^{2} - 7 \, {\left (203 \, B a^{2} b^{2} - 85 \, A a b^{3}\right )} d x - 70 \, {\left (12 \, B a^{3} b - 5 \, A a^{2} b^{2}\right )} d\right )} e^{2} - {\left (464 \, B b^{4} d^{2} x^{2} + {\left (1303 \, B a b^{3} - 195 \, A b^{4}\right )} d^{2} x + 7 \, {\left (107 \, B a^{2} b^{2} - 15 \, A a b^{3}\right )} d^{2}\right )} e\right )} \sqrt {x e + d}}{60 \, {\left (b^{7} x^{2} + 2 \, a b^{6} x + a^{2} b^{5}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 607 vs.
\(2 (268) = 536\).
time = 1.69, size = 607, normalized size = 2.22 \begin {gather*} \frac {7 \, {\left (4 \, B b^{3} d^{3} e - 17 \, B a b^{2} d^{2} e^{2} + 5 \, A b^{3} d^{2} e^{2} + 22 \, B a^{2} b d e^{3} - 10 \, A a b^{2} d e^{3} - 9 \, B a^{3} e^{4} + 5 \, A a^{2} b e^{4}\right )} \arctan \left (\frac {\sqrt {x e + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{4 \, \sqrt {-b^{2} d + a b e} b^{5}} - \frac {4 \, {\left (x e + d\right )}^{\frac {3}{2}} B b^{4} d^{3} e - 4 \, \sqrt {x e + d} B b^{4} d^{4} e - 25 \, {\left (x e + d\right )}^{\frac {3}{2}} B a b^{3} d^{2} e^{2} + 13 \, {\left (x e + d\right )}^{\frac {3}{2}} A b^{4} d^{2} e^{2} + 27 \, \sqrt {x e + d} B a b^{3} d^{3} e^{2} - 11 \, \sqrt {x e + d} A b^{4} d^{3} e^{2} + 38 \, {\left (x e + d\right )}^{\frac {3}{2}} B a^{2} b^{2} d e^{3} - 26 \, {\left (x e + d\right )}^{\frac {3}{2}} A a b^{3} d e^{3} - 57 \, \sqrt {x e + d} B a^{2} b^{2} d^{2} e^{3} + 33 \, \sqrt {x e + d} A a b^{3} d^{2} e^{3} - 17 \, {\left (x e + d\right )}^{\frac {3}{2}} B a^{3} b e^{4} + 13 \, {\left (x e + d\right )}^{\frac {3}{2}} A a^{2} b^{2} e^{4} + 49 \, \sqrt {x e + d} B a^{3} b d e^{4} - 33 \, \sqrt {x e + d} A a^{2} b^{2} d e^{4} - 15 \, \sqrt {x e + d} B a^{4} e^{5} + 11 \, \sqrt {x e + d} A a^{3} b e^{5}}{4 \, {\left ({\left (x e + d\right )} b - b d + a e\right )}^{2} b^{5}} + \frac {2 \, {\left (3 \, {\left (x e + d\right )}^{\frac {5}{2}} B b^{12} e + 10 \, {\left (x e + d\right )}^{\frac {3}{2}} B b^{12} d e + 45 \, \sqrt {x e + d} B b^{12} d^{2} e - 15 \, {\left (x e + d\right )}^{\frac {3}{2}} B a b^{11} e^{2} + 5 \, {\left (x e + d\right )}^{\frac {3}{2}} A b^{12} e^{2} - 135 \, \sqrt {x e + d} B a b^{11} d e^{2} + 45 \, \sqrt {x e + d} A b^{12} d e^{2} + 90 \, \sqrt {x e + d} B a^{2} b^{10} e^{3} - 45 \, \sqrt {x e + d} A a b^{11} e^{3}\right )}}{15 \, b^{15}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.33, size = 561, normalized size = 2.05 \begin {gather*} \left (\frac {2\,A\,e^2-2\,B\,d\,e}{3\,b^3}+\frac {2\,B\,e\,\left (3\,b^3\,d-3\,a\,b^2\,e\right )}{3\,b^6}\right )\,{\left (d+e\,x\right )}^{3/2}+\left (\frac {\left (\frac {2\,A\,e^2-2\,B\,d\,e}{b^3}+\frac {2\,B\,e\,\left (3\,b^3\,d-3\,a\,b^2\,e\right )}{b^6}\right )\,\left (3\,b^3\,d-3\,a\,b^2\,e\right )}{b^3}-\frac {6\,B\,e\,{\left (a\,e-b\,d\right )}^2}{b^5}\right )\,\sqrt {d+e\,x}-\frac {{\left (d+e\,x\right )}^{3/2}\,\left (-\frac {17\,B\,a^3\,b\,e^4}{4}+\frac {19\,B\,a^2\,b^2\,d\,e^3}{2}+\frac {13\,A\,a^2\,b^2\,e^4}{4}-\frac {25\,B\,a\,b^3\,d^2\,e^2}{4}-\frac {13\,A\,a\,b^3\,d\,e^3}{2}+B\,b^4\,d^3\,e+\frac {13\,A\,b^4\,d^2\,e^2}{4}\right )-\sqrt {d+e\,x}\,\left (\frac {15\,B\,a^4\,e^5}{4}-\frac {49\,B\,a^3\,b\,d\,e^4}{4}-\frac {11\,A\,a^3\,b\,e^5}{4}+\frac {57\,B\,a^2\,b^2\,d^2\,e^3}{4}+\frac {33\,A\,a^2\,b^2\,d\,e^4}{4}-\frac {27\,B\,a\,b^3\,d^3\,e^2}{4}-\frac {33\,A\,a\,b^3\,d^2\,e^3}{4}+B\,b^4\,d^4\,e+\frac {11\,A\,b^4\,d^3\,e^2}{4}\right )}{b^7\,{\left (d+e\,x\right )}^2-\left (2\,b^7\,d-2\,a\,b^6\,e\right )\,\left (d+e\,x\right )+b^7\,d^2+a^2\,b^5\,e^2-2\,a\,b^6\,d\,e}+\frac {2\,B\,e\,{\left (d+e\,x\right )}^{5/2}}{5\,b^3}+\frac {7\,e\,\mathrm {atan}\left (\frac {\sqrt {b}\,e\,{\left (a\,e-b\,d\right )}^{3/2}\,\sqrt {d+e\,x}\,\left (5\,A\,b\,e-9\,B\,a\,e+4\,B\,b\,d\right )}{-9\,B\,a^3\,e^4+22\,B\,a^2\,b\,d\,e^3+5\,A\,a^2\,b\,e^4-17\,B\,a\,b^2\,d^2\,e^2-10\,A\,a\,b^2\,d\,e^3+4\,B\,b^3\,d^3\,e+5\,A\,b^3\,d^2\,e^2}\right )\,{\left (a\,e-b\,d\right )}^{3/2}\,\left (5\,A\,b\,e-9\,B\,a\,e+4\,B\,b\,d\right )}{4\,b^{11/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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